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    Work Calculator

    Pulling with 50 N at 60° over 10 m does 250 J of work: only the forward component F cos θ = 25 N moves the sled.

    Solve for:
    °
    Work W =

    500 J

    In kJ
    0.5 kJ
    In MJ
    0.0005 MJ
    In cal
    119.5028681 cal
    In kcal
    0.1195028681 kcal
    In Wh
    0.1388888889 Wh
    Step-by-step solution
    1. W = F × d × cos θ°
    2. W = 50 × 10 × cos 0°
    3. W = 500 J

    Work Formula

    W = F d cos θ

    W work (J), F force, d displacement, θ angle between force and motion

    Worked Example

    Pulling a sled 10 m with 50 N at 60° to the ground:

    1. W = F × d × cos θ°
    2. W = 50 × 10 × cos 60°
    3. W = 250 J

    In MJ: 0.00025 MJ · In cal: 59.75143403 cal · In kcal: 0.05975143403 kcal · In Wh: 0.06944444444 Wh

    One joule

    A joule is one newton acting over one metre. Lifting a 100 g apple 1 m takes about 1 J; a food Calorie (kcal) is 4184 J.

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    Frequently asked questions

    When is work zero?

    When the force is perpendicular to the motion (θ = 90°) or nothing moves. Carrying a bag level along a corridor does no work on it in the physics sense.

    What does negative work mean?

    The force opposes the motion (θ > 90°), taking energy away, as friction and braking forces do.

    Sources

    Last reviewed: . Factors are stored exactly and computed with 50-digit decimal arithmetic. See how we verify conversion factors.

    Cite this page

    APA

    Scientific Converters. (2026, October 15). Work Calculator. Retrieved October 25, 2026, from https://scientificconverters.com/calculators/work-calculator/

    IEEE

    Scientific Converters, "Work Calculator," scientificconverters.com. Accessed: Oct. 25, 2026. [Online]. Available: https://scientificconverters.com/calculators/work-calculator/

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