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    Second-Order System Calculator

    A second-order system with ζ = 0.5 and ωₙ = 4 rad/s overshoots by 16.3034 %, peaks at 0.907 s and settles within 2 % in about 2 s.

    Given:
    Peak overshoot Mₚ =

    16.303353482158 %

    Full answer, then cut to fewer decimals (not rounded):

    • 16.303353482158 %
    • 16.30335348215 %
    • 16.3033534821 %
    • 16.303353482 %
    • 16.30335348 %
    • 16.3033534 %
    • 16.303353 %
    • 16.30335 %
    • 16.3033 %
    • 16.303 %
    • 16.30 %
    • 16.3 %
    Damping ratio ζ
    0.5
    Natural frequency ωₙ
    4 rad/s
    Damped frequency ω_d = ωₙ√(1 − ζ²)
    3.464101615 rad/s
    Peak time tₚ = π/ω_d
    0.9068996821 s
    Rise time t_r = (π − θ)/ω_d
    0.6045997881 s
    Settling time, 2 % (4/ζωₙ)
    2 s
    Settling time, 5 % (3/ζωₙ)
    1.5 s
    Poles
    −2 ± j3.4641
    Response
    underdamped
    Step-by-step solution
    1. Mₚ = e^(−ζπ/√(1 − ζ²)) = e^(−1.813799364) = 0.1630335348
    2. tₚ = π ÷ ω_d = 0.9068996821 s; t_s(2 %) = 4 ÷ (ζωₙ) = 2 s

    Second-Order System Formula

    Mₚ = e^(−ζπ/√(1−ζ²)), tₚ = π/ω_d

    ω_d = ωₙ√(1 − ζ²), t_r = (π − arccos ζ)/ω_d, t_s ≈ 4/(ζωₙ) (2 %)

    Worked Example

    A system with ζ = 0.5 and ωₙ = 4 rad/s (s² + 4s + 16):

    1. Mₚ = e^(−ζπ/√(1 − ζ²)) = e^(−1.813799364) = 0.1630335348
    2. tₚ = π ÷ ω_d = 0.9068996821 s; t_s(2 %) = 4 ÷ (ζωₙ) = 2 s

    Natural frequency ωₙ: 4 rad/s · Damped frequency ω_d = ωₙ√(1 − ζ²): 3.464101615 rad/s · Peak time tₚ = π/ω_d: 0.9068996821 s · Rise time t_r = (π − θ)/ω_d: 0.6045997881 s · Settling time, 2 % (4/ζωₙ): 2 s · Settling time, 5 % (3/ζωₙ): 1.5 s · Poles: −2 ± j3.4641 · Response: underdamped

    GATE tip

    Overshoot depends on ζ alone: 0.4 → 25.4 %, 0.5 → 16.3 %, 0.6 → 9.5 %, 0.707 → 4.3 %, 0.8 → 1.5 %. Memorise a few and you can work backwards from a stated overshoot.

    More Control Systems Calculators

    Frequently asked questions

    How do I read ζ and ωₙ from a transfer function?

    Write the denominator as s² + 2ζωₙs + ωₙ². For s² + 4s + 16: ωₙ = 4 and 2ζωₙ = 4, so ζ = 0.5.

    Why are settling times approximate?

    t_s = 4/(ζωₙ) uses the decaying envelope e^(−ζωₙt) and ignores the oscillation, so the true time can be a little shorter.

    Sources

    Last reviewed: . Factors are stored exactly and computed with 50-digit decimal arithmetic. See how we verify conversion factors.

    Cite this page

    APA

    Scientific Converters. (2026, October 15). Second-Order System Calculator. Retrieved October 25, 2026, from https://scientificconverters.com/calculators/second-order-system-calculator/

    IEEE

    Scientific Converters, "Second-Order System Calculator," scientificconverters.com. Accessed: Oct. 25, 2026. [Online]. Available: https://scientificconverters.com/calculators/second-order-system-calculator/

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