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    Oblique Shock Calculator

    A Mach 2 flow turned by a 10° wedge forms an attached oblique shock at β = 39.3139 °, leaving the flow at Mach 1.64 with 1.71 times the pressure.

    °

    Air 1.4; hot combustion gases about 1.3; helium 1.667.

    Shock wave angle β (weak) =

    39.3139318448189 °

    Full answer, then cut to fewer decimals (not rounded):

    • 39.3139318448189 °
    • 39.313931844818 °
    • 39.31393184481 °
    • 39.3139318448 °
    • 39.313931844 °
    • 39.31393184 °
    • 39.3139318 °
    • 39.313931 °
    • 39.31393 °
    • 39.3139 °
    • 39.313 °
    • 39.31 °
    • 39.3 °
    Downstream Mach number M₂
    1.640522229
    Pressure ratio p₂/p₁
    1.706578604
    Temperature ratio T₂/T₁
    1.170151284
    Density ratio ρ₂/ρ₁
    1.458425613
    Stagnation pressure ratio p₀₂/p₀₁
    0.9846440225
    Normal Mach component M₁ sin β
    1.267138036
    Strong-shock solution β
    83.70008038 °
    Maximum deflection θ_max at this Mach
    22.97353173 °
    Step-by-step solution
    1. Solve tan θ = 2 cot β (M₁² sin²β − 1) ÷ (M₁²(γ + cos 2β) + 2) for β → 39.31393184° (weak)
    2. Mₙ₁ = M₁ sin β = 1.267138036; normal-shock relations give Mₙ₂ and the ratios
    3. M₂ = Mₙ₂ ÷ sin(β − θ) = 1.640522229

    Oblique Shock Formula

    tan θ = 2 cot β (M₁² sin²β − 1) / (M₁²(γ + cos 2β) + 2)

    normal component M₁ sin β obeys the normal-shock relations; M₂ = Mₙ₂ / sin(β − θ)

    Worked Example

    Mach 2 flow turned by a 10° wedge:

    1. Solve tan θ = 2 cot β (M₁² sin²β − 1) ÷ (M₁²(γ + cos 2β) + 2) for β → 39.31393184° (weak)
    2. Mₙ₁ = M₁ sin β = 1.267138036; normal-shock relations give Mₙ₂ and the ratios
    3. M₂ = Mₙ₂ ÷ sin(β − θ) = 1.640522229

    Pressure ratio p₂/p₁: 1.706578604 · Temperature ratio T₂/T₁: 1.170151284 · Density ratio ρ₂/ρ₁: 1.458425613 · Stagnation pressure ratio p₀₂/p₀₁: 0.9846440225 · Normal Mach component M₁ sin β: 1.267138036 · Strong-shock solution β: 83.70008038 ° · Maximum deflection θ_max at this Mach: 22.97353173 °

    GATE tip

    A supersonic diamond airfoil sees an oblique shock at the leading edge, a Prandtl–Meyer expansion at the shoulder and a shock at the trailing edge; the pressure difference gives wave drag.

    More Compressible Flow Calculators

    Frequently asked questions

    Weak or strong solution?

    Two shock angles satisfy the relation; in external flows the weak one almost always occurs. The strong one needs a high downstream pressure.

    What happens above θ_max?

    No attached oblique shock can turn the flow, so a detached bow shock stands ahead of the body.

    Sources

    Last reviewed: . Factors are stored exactly and computed with 50-digit decimal arithmetic. See how we verify conversion factors.

    Cite this page

    APA

    Scientific Converters. (2026, October 15). Oblique Shock Calculator. Retrieved October 25, 2026, from https://scientificconverters.com/calculators/oblique-shock-calculator/

    IEEE

    Scientific Converters, "Oblique Shock Calculator," scientificconverters.com. Accessed: Oct. 25, 2026. [Online]. Available: https://scientificconverters.com/calculators/oblique-shock-calculator/

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